replaceAll in JavaScript

String.prototype.replaceAll() replaces all occurrence of a string with another string value.

Syntax:

const newStr = str.replaceAll(regexp|substr, newSubstr|function)

There are few ways to replace all occurrence of a string:

RegEx
split and join
replaceAll

1. RegEx 🙅‍♀️

const info = "Hi All, suprabha's account is @suprabha";
const newInfo = info.replace(/suprabha/g, "suprabha supi");
console.log(newInfo); // "Hi All, suprabhasupi's account is @suprabhasupi"

2. split and join ䷖ ⊞

Using split and join, replace all the occurrence of a string.

const info = "Hi All, suprabha's account is @suprabha";
const newInfo = info.split('suprabha').join('suprabhasupi');
console.log(newInfo); // "Hi All, suprabhasupi's account is @suprabhasupi"

Till now, you were able to do full replacement with above two approaches. Now we have replaceAll which helps us to do the same.

3. replaceAll 🚀

The Mathias bynens proposal solves these problems and gives a very easy way to do substring replacement using replaceAll() which replaces all instances of a substring in a string with another string value without using a global regexp.

const info = "Hi All, suprabha's account is @suprabha";
const newInfo = info.replaceAll('suprabha','suprabhasupi');
console.log(newInfo); // "Hi All, suprabhasupi's account is @suprabhasupi"

You can also pass RegEx to first parameter in replaceAll.

const info = "Hi All, suprabha's account is @suprabha";
const regex = /suprabha/ig;
const newInfo = info.replaceAll(regex,'suprabhasupi');
console.log(newInfo); // "Hi All, suprabhasupi's account is @suprabhasupi"

Note: 🧨

When using a regexp you have to set the global ("g") flag; otherwise, it will throw a TypeError: "replaceAll must be called with a global RegExp".

You also have replace() method, which replaces only the first occurrence if the input pattern is a string.

const info = "Hi All, suprabha's account is @suprabha";
const newInfo = info.replace("suprabha", "suprabhasupi");
console.log(newInfo); // "Hi All, suprabhasupi's account is @suprabha"